h^2+12h+16=0

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Solution for h^2+12h+16=0 equation:


Simplifying
h2 + 12h + 16 = 0

Reorder the terms:
16 + 12h + h2 = 0

Solving
16 + 12h + h2 = 0

Solving for variable 'h'.

Begin completing the square.

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + 12h + -16 + h2 = 0 + -16

Reorder the terms:
16 + -16 + 12h + h2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 12h + h2 = 0 + -16
12h + h2 = 0 + -16

Combine like terms: 0 + -16 = -16
12h + h2 = -16

The h term is 12h.  Take half its coefficient (6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
12h + 36 + h2 = -16 + 36

Reorder the terms:
36 + 12h + h2 = -16 + 36

Combine like terms: -16 + 36 = 20
36 + 12h + h2 = 20

Factor a perfect square on the left side:
(h + 6)(h + 6) = 20

Calculate the square root of the right side: 4.472135955

Break this problem into two subproblems by setting 
(h + 6) equal to 4.472135955 and -4.472135955.

Subproblem 1

h + 6 = 4.472135955 Simplifying h + 6 = 4.472135955 Reorder the terms: 6 + h = 4.472135955 Solving 6 + h = 4.472135955 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + h = 4.472135955 + -6 Combine like terms: 6 + -6 = 0 0 + h = 4.472135955 + -6 h = 4.472135955 + -6 Combine like terms: 4.472135955 + -6 = -1.527864045 h = -1.527864045 Simplifying h = -1.527864045

Subproblem 2

h + 6 = -4.472135955 Simplifying h + 6 = -4.472135955 Reorder the terms: 6 + h = -4.472135955 Solving 6 + h = -4.472135955 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + h = -4.472135955 + -6 Combine like terms: 6 + -6 = 0 0 + h = -4.472135955 + -6 h = -4.472135955 + -6 Combine like terms: -4.472135955 + -6 = -10.472135955 h = -10.472135955 Simplifying h = -10.472135955

Solution

The solution to the problem is based on the solutions from the subproblems. h = {-1.527864045, -10.472135955}

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